应用被加密了,破不开怎么办?

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select * from tbl_Articles_data WHERE ArticleID=1819720 LIMIT 0,1
select * from tbl_Articles_sphinx where id=1819720 LIMIT 0,1
SELECT ArticleID,Title FROM tbl_Articles WHERE ArticleID IN(1102190,3267822,1128087,1124414,1122601,1118827,514583,1129219,1122084,1275283,1093246,1112318,1096589,1131173,1121638,1482941,1127355,1125239,987313,1086626,1120151,1050701,1087895,1123987,1056488,1121124,535519,1125091,1069165,1112144) ORDER BY field (ArticleID,1102190,3267822,1128087,1124414,1122601,1118827,514583,1129219,1122084,1275283,1093246,1112318,1096589,1131173,1121638,1482941,1127355,1125239,987313,1086626,1120151,1050701,1087895,1123987,1056488,1121124,535519,1125091,1069165,1112144)