地图上的比例尺如何定义

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select * from tbl_Articles WHERE ArticleID=2692578 LIMIT 0,1
select * from tbl_Articles_data WHERE ArticleID=2692578 LIMIT 0,1
select * from tbl_Articles_sphinx where id=2692578 LIMIT 0,1
SELECT ArticleID,Title FROM tbl_Articles WHERE ArticleID IN(1077960,1098207,1091065,1107062,1071619,1085008,1078883,1102282,1083383,1095137,1093206,1051239,1073832,1103386,1058843,1091404,1088774,1070967,1057710,1095888,1069159,1100583,1099865,1070058,1065713,1067207,1048506,1085372,1062602,1045867) ORDER BY field (ArticleID,1077960,1098207,1091065,1107062,1071619,1085008,1078883,1102282,1083383,1095137,1093206,1051239,1073832,1103386,1058843,1091404,1088774,1070967,1057710,1095888,1069159,1100583,1099865,1070058,1065713,1067207,1048506,1085372,1062602,1045867)