word求平均值的公式

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select * from tbl_Articles WHERE ArticleID=2966580 LIMIT 0,1
select * from tbl_Articles_data WHERE ArticleID=2966580 LIMIT 0,1
select * from tbl_Articles_sphinx where id=2966580 LIMIT 0,1
SELECT ArticleID,Title FROM tbl_Articles WHERE ArticleID IN(1102720,2301054,645235,1093977,98875,1116641,1086786,1303844,1104693,98806,684250,1118789,82220,705577,632099,634327,654938,597391,585365,1081993,512230,1303322,440123,1117399,1119099,746083,711754,680970,1117746,668515) ORDER BY field (ArticleID,1102720,2301054,645235,1093977,98875,1116641,1086786,1303844,1104693,98806,684250,1118789,82220,705577,632099,634327,654938,597391,585365,1081993,512230,1303322,440123,1117399,1119099,746083,711754,680970,1117746,668515)